Solution
[tex]\begin{gathered} 7\times6\div(13-10)+4 \\ \\ Bracket\text{ First and then Subtract}:(13-10)=(3) \\ \\ 7\times6\div(3)+4 \\ 7\times6\div3+4 \\ \\ Divide\text{ next which will be}:6\div3=2 \\ \\ 7\times2+4 \\ \\ Multiply\text{ is next}:7\times2=14 \\ \\ 14+4 \\ \\ The\text{ last is addition}:14+4=18 \\ \\ 18 \end{gathered}[/tex]The operation will be in the order
[tex]\begin{gathered} Subtraction \\ \\ Division \\ \\ Multiplication \\ \\ Addition \end{gathered}[/tex]