To find the y-intercept we going to set x=0
[tex]\begin{gathered} f(x)=\log_2\left(x+3\right)+1 \\ f(x)=\operatorname{\log}_2(0+3)+1 \\ f(x)=\operatorname{\log}_2(3)+1 \end{gathered}[/tex]But we don't have exactly that value on the answer
So we need to apply logarithm properties, in this case, base change
[tex]\log_ba=\frac{\log_ca}{\operatorname{\log}_cb}[/tex]Appling to our problem
[tex]f(x)=\frac{\operatorname{\log}3}{\operatorname{\log}2}+1[/tex]Answer: Option B log3/log2+1
