JorahH463547
JorahH463547
29-10-2022
Mathematics
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this one is super hard
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KionteP620111
KionteP620111
29-10-2022
[tex]\begin{gathered} \text{Answer} \\ \log _b6 \end{gathered}[/tex]
Explanation
According to the laws of logarithms
[tex]\begin{gathered} \text{Log}_ax+log_aY=log_aXY \\ \text{Therefore, } \\ \log _b2+log_b\text{ 3} \\ =log_b\text{ (2 x 3)} \\ =log_b6 \end{gathered}[/tex]
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