For the given question, we will match each trinomial to its factored form.
So, we will factor each given trinomial:
[tex]3y^2-2y-8[/tex]
The factors of the trinomial will be:
[tex](y-2)(3y+4)[/tex]
And the second trinomial:
[tex]3y^2+2y-8=(y+2)(3y-4)[/tex]
The third trinomial will be:
[tex]3y^2-13y-10=(y-5)(3y+2)[/tex]
The fourth trinomial will be:
[tex]3y^2+13y-10=(y+5)(3y-2)[/tex]
