we have
(2x-9)/(x-7) + x/2 = 5/(x-7)
solve for x
Multiply both sides by (x-7)
(2x-9)+(x-7)x/2=5
Multiply by 2 both sides
4x-18+x^2-7x=10
Group terms
x^2-3x-28=0
Solve the quadrativ equation by the formula
we have
a=1
b=-3
c=-28
REmember that the formula of quadratic equation is
[tex]x=\frac{-b_{\pm\sqrt[]{b^2\text{ -4ac}}}}{2a}[/tex]substitute the given values in the formula
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