We can solve it doing the next thing
[tex]\begin{gathered} \frac{2}{y}+\frac{4}{y}=2 \\ \frac{2y+4y}{y^2}=2 \\ \frac{(2+4)y}{y^2}=2 \\ \frac{(2+4)}{y}=2 \\ (2+4)=2y \\ 6=2y \\ y=\frac{6}{2}=3 \end{gathered}[/tex]
So the answer is A. the set solution is { 3 }.
