Explanation:
To solve this question, we need to calculate each molar mass of each compound:
C2H6O = (12*2)+(6*1)+(16*1) = 46 g/mol
CHF3 = 12+1+(19*3) = 70 g/mol
CO2 = 12 + (16*2) = 44 g/mol
N2O =(14*2)+16 = 44 g/mol
H2O2 = 32 + 2 = 34 g/mol
C4H10 = (12*4)+10 = 58 g/mol
Answer: CHF3 = 12+1+(19*3) = 70 g/mol
