The given function is
[tex]f(x)=\frac{6x}{x^2-36}[/tex]
To find the zeros of this function, we replace f(x) = 0 and solve for x
[tex]0=\frac{6x}{x^2-36}[/tex]
Then,
[tex]\begin{gathered} 0\cdot(x^2-36)=6x \\ 6x=0 \\ x=0 \end{gathered}[/tex]
This means the function has a unique root, x = 0.
The image below shows the graph of this function, there you can observe the zero of the function we found.
Therefore, the answer is x = 0.
