Notice that in this case, we want to combine 50 employees for a committee of 6 people. Since the order in which an employee does not matter, we have the following:
[tex]\frac{50\cdot49\cdot48\cdot47\cdot46\cdot45}{6!}=15,890,700[/tex]therefore, there are 15,890,700 ways in the committee could be selected
