Answer:
f(g(1)) = 15.
Explanation:
Given f(x) and g(x) defined below:
[tex]$f\mleft(x\mright)=3x,g\mleft(x\mright)=x+4$[/tex]To evaluate f(g(1)), first find g(1):
[tex]\begin{gathered} g(x)=x+4 \\ g(1)=1+4 \\ g(1)=5 \end{gathered}[/tex]Thus:
[tex]\begin{gathered} f\mleft(g\mleft(1\mright)\mright)=f(5) \\ f(x)=3x \\ \implies f(5)=3\times5 \\ =15 \end{gathered}[/tex]Therefore, the value of f(g(1)) is 15.
