It is given that:
[tex]f(x)=6^x-4x;g(x)=\frac{1}{2}x+10[/tex]
So the value of f(2)-g(-2) is given by substituting x=2 in f(x) and x=-2 in g(x) as shown below;
[tex]\begin{gathered} 6^2-4(2)-\lbrack\frac{1}{2}(-2)+10\rbrack=36-8-\lbrack-1+10\rbrack \\ =28-9 \\ =19 \end{gathered}[/tex]
So the value is 19.
