Given the function:
[tex]f(x)=\frac{-3}{4}x+6[/tex]
First, we find the intercepts.
When x=0:
[tex]\begin{gathered} f(x)=\frac{-3}{4}x+6 \\ f(0)=\frac{-3}{4}(0)+6=6 \\ \implies(0,6) \end{gathered}[/tex]
The y-intercept is at (0,6).
When y=0:
[tex]\begin{gathered} f(x)=-\frac{3}{4}x+6 \\ 0=-\frac{3}{4}x+6 \\ \frac{3x}{4}=6 \\ x=6\times\frac{4}{3} \\ x=8 \\ \implies(8,0) \end{gathered}[/tex]
The x-intercept is at (8, 0).
