KaymarieE409879 KaymarieE409879

29-10-2022
Mathematics

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How do I do this, I’m unsure how to go about it

How do I do this Im unsure how to go about it class=

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AnikenD693282 AnikenD693282

29-10-2022

We will have the following:

[tex]\begin{gathered} \sqrt{\frac{6}{x}}\ast\sqrt{\frac{x^2}{24}}=\sqrt{\frac{6}{x}\ast\frac{x^2}{24}} \\ \\ =\sqrt{\frac{x}{4}}=\frac{\sqrt{x}}{2} \end{gathered}[/tex]

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