AndricE352255 AndricE352255
  • 28-10-2022
  • Mathematics
contestada

Hello! I was wondering how I would solve this problem .[tex] log_{11}(35 + 3x { }^{2} ) = log_{11}(4x ^{2} - 2x)[/tex]

Respuesta :

ChaseN152948 ChaseN152948
  • 28-10-2022

Answer: x = 7 or -5

Explanation

Log₁₁(35 + 3x²) = Log₁₁(4x² - 2x)

⇒ 35 + 3x² = 4x² - 2x

4x² - 2x = 3x² + 35

By grouping th terms,

4x² - 3x² - 2x - 35 = 0

x² - 2x - 35 = 0

By factorization, we have

x² - 7x + 5x - 35 = 0

x(x-7) + 5(x-7) = 0

(x-7)(x+5) = 0

Either x-7 = 0 or x+5 = 0

∴ x = 7 or -5

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