DollieQ701187 DollieQ701187
  • 28-10-2022
  • Mathematics
contestada

find the equation of the parabola with its focus at -5,0 and it's directrix y = 2

find the equation of the parabola with its focus at 50 and its directrix y 2 class=

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NicklasJ506898 NicklasJ506898
  • 28-10-2022

Recall that a parabola is a curve where any point is at an equal distance from the focus and the directrix, if (x,y) is a point on the parabola then:

[tex]\sqrt[]{(-5-x)^2+(y-0)^2}=2-y\text{.}[/tex]

Solving for y we get:

[tex]\begin{gathered} (-5-x)^2+y^2=(2-y)^2, \\ (x+5)^2+y^2=4-4y+y^2, \\ -4y=(x+5)^2-4, \\ y=-\frac{1}{4}(x+5)^2+\frac{4}{4}, \\ y=-\frac{1}{4}(x+5)^2+1. \end{gathered}[/tex]

Answer: Second option.

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