DamainZ500491 DamainZ500491
  • 28-10-2022
  • Mathematics
contestada

What is the equation of the quadratic function that has a minimum at (7,-3) and goes through (9,9)? f(x) = __(x − __)² + __

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DuruL28241 DuruL28241
  • 28-10-2022

First, let's look at the vertex form of the quadratic equation:

[tex]y=a(x-h)^2+k[/tex]

Where the vertex is located at (h, k).

The vertex is the point of maximum or minimum of the quadratic function.

So if the minimum is at (7, -3), we have h = 7 and k = -3.

Then, to find the value of a, let's use the point (9, 9) in the function:

[tex]\begin{gathered} y=a(x-7)^2-3\\ \\ 9=a(9-7)^2-3\\ \\ 9=4a-3\\ \\ 4a=12\\ \\ a=3 \end{gathered}[/tex]

Therefore the function is f(x) = 3(x - 7)² - 3.

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