Jessica has money in two savings accounts. One rate is 7% and the other is 13%. If she has $800 more in the 13% account and the total interest is $333, how much is invested in each savings account?

Respuesta :

Given:

Account 1:

Principal amount (P)= x

Rate (R) = 7%

Account 2:

Principal amount (p) = x+800

Rate (R) = 13%

Total interest = $333

The simple interest is given as,

[tex]\begin{gathered} I=\text{PRN} \\ I_1+I_2=333 \\ x\times\frac{7}{100}\times1+(x+800)\times\frac{13}{100}\times1=333 \\ x\times\frac{7}{100}+(x+800)\times\frac{13}{100}=333 \\ 0.07x+0.13x+104=333 \\ 0.2x=229 \\ x=\frac{229}{0.2} \\ x=1145 \end{gathered}[/tex]

So, the amount in account 1 is x = $1145

Account 2: x+800= $1945

The interest in each account is,

Account 1 :

[tex]\begin{gathered} I_1=x\times\frac{7}{100}\times1 \\ =1145\times\frac{7}{100} \\ =80.15 \end{gathered}[/tex]

Account 2:

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