The standard form of the equation of a circle is given by
[tex](x-a)^2+(y-b^{})^2=r^2[/tex]
where a and b are the center of the circle and r = radius of the circle
From the question given
a = -3
b= -4
r = 5
[tex]\begin{gathered} (x-(-3))^2+(y-(-4))^2=5^2 \\ \\ (x+3)^2+(y+4)^2=5^2 \end{gathered}[/tex]
[tex]\text{Standard form of the circle = }(x+3)^2+(y+4)^2=5^2[/tex]
