LeanL314055 LeanL314055

28-10-2022
Physics

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It takes Josh 8 seconds to slow down from 39 m/s to 21 m/s. Calculate his acceleration

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FallouG759894 FallouG759894

28-10-2022

a: acceleration

Δv: change in velocity

t: time

a = Δv/t = (21-39)/8 = -18/8 m/s^2 = -2.25 m/s^2

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