We have the slope-intercept form of a line
[tex]y=mx+b[/tex]where m is the slope and b is the y-intercept
Parallel line have the same slope so the slope of the line that we are searching is m=3
so we will use the slope-point form
[tex]y-y_1=m(x-x_1)[/tex]where
m=3
x1=-2
y1=-8
then we substitute the values
[tex]y+8=3(x+2)[/tex]