Respuesta :

Notice that

[tex]\begin{gathered} \lim_{x\to11^+}F(x)=+\infty \\ and \\ \lim_{x\rightarrow11^-}F(x)=-\infty \end{gathered}[/tex]

Since the denominator of the function vanishes as x->11.

Therefore, the vertical asymptote of F(x) is x=11

Otras preguntas