[tex]\begin{gathered} a_1=first\text{ term=11} \\ r=\text{common ratio=}2 \end{gathered}[/tex]
Therefore,
[tex]n_{th\text{ }}term=ar^{n-1}[/tex][tex]\begin{gathered} 6th\text{ term=11}\times2^{6-1} \\ 6th\text{ term}=11\times2^5 \\ 6th\text{ term}=11\times32 \\ 6th\text{ term}=352\text{ } \end{gathered}[/tex]
