MarishkaW599047 MarishkaW599047
  • 27-10-2022
  • Mathematics
contestada

If f(x) = x - 3, g(x) = 2x - 6, and h(x) = x^2 - 6x + 9, then (h - fg)(-1)=

If fx x 3 gx 2x 6 and hx x2 6x 9 then h fg1 class=

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MalikaiU103789 MalikaiU103789
  • 27-10-2022

The function h - fg is given by:

[tex]\begin{gathered} (h-fg)(x)=h(x)-(fg)(x) \\ =h(x)-f(x)\cdot g(x) \end{gathered}[/tex]

Therefore,

[tex]\begin{gathered} (h-fg)(x)=(x^2-6x+9)-(x-3)(2x-6) \\ =(x-3)^2-2(x-3)^2 \\ =-(x-3)^2 \end{gathered}[/tex]

Therefore,

[tex](h-fg)(-1)=-(-1-3)^2=-(-4)^2=-16[/tex]

Therefore,

(h - fg)(-1) = -16

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