Answer:
• Amplitude = 3
,
• Period = π/2
Explanation:
Given the function:
[tex]y=3\sin(4x)[/tex]
Compared with the general sine function:
[tex]y=a\sin(bx+c)+d[/tex]
We have that:
[tex]\begin{gathered} \text{ Its amplitude}=|a|=3 \\ \text{ Period}=\frac{2\pi}{|b|}=\frac{2\pi}{4}=\frac{1}{2}\pi \end{gathered}[/tex]
Next, a sketch of one cycle of the function is given below:
