SOLUTION
Which of the following is equivalent to the radical expression below when x≥0
[tex]\sqrt{2x}.\sqrt{x+3}[/tex]
Multiplying the root of the equation
[tex]\begin{gathered} \sqrt{2x}.\sqrt{x+3} \\ \sqrt{2x(x+3)} \\ \sqrt{2x^2+6x} \end{gathered}[/tex]
Therefore the correct answer is
[tex]\sqrt{2x^2+6x}[/tex]
Option C
