We would solve the given system of equatons by applying the method of elimination. We would eliminate y by adding the first equation to the second equation. It becomes
2x + - x + 3y + - 3y = - 12 + 18
2x - x + 3y - 3y = 6
x + 0 = 6
x = 6
Substituting x = 6 into the second equation, it becomes
- 6 - 3y = 18
- 3y = 18 + 6
- 3y = 24
y = 24/-3
y = - 8
The solution is (6, - 8)
