Given:
[tex]2x^2+20x+48[/tex]To find the factors:
The given equation can be written as,
[tex]\begin{gathered} 2x^2+20x+48=2x^2+8x+12x+48 \\ =2x(x+4)+12(x+4)_{} \\ =(x+4)(2x+12)_{} \\ =2(x+4)(x+6) \end{gathered}[/tex]Hence, the factors are 2,(x+4), and (x+6).
