Since the angles ABD and DBC are supplementary angles, then:
[tex]m\angle ABD+m\angle BDC=180[/tex]Substitute the given values for those angles and solve for Y:
[tex]\begin{gathered} \Rightarrow152+y=180 \\ \Rightarrow y=180-152 \\ \Rightarrow y=28 \end{gathered}[/tex]Therefore, the answer is:
[tex]y=28^{\circ}[/tex]