Given the polynomial below
[tex](x^3-8x+6)\div(x^2-2x+1)[/tex]
Using the long division method
The answer in the equivalent form
[tex]_{}q(x)+\frac{r(x)}{b(x)_{}}[/tex]
Where
[tex]\begin{gathered} q(x)=quotient=x+2 \\ r(x)=\text{remainder}=-5x+4 \\ b(x)=\text{divisor}=x^2-2x+1 \end{gathered}[/tex]
The answer is
[tex]q(x)+\frac{r(x)}{b(x)_{}}=(x+2)+\frac{-5x+4}{x^2-2x+1}[/tex]
