IsidoreM317082 IsidoreM317082
  • 26-10-2022
  • Mathematics
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What is the diameter of a sphere with a volume of 80487 in^3, to the nearest tenth ofan inch?

What is the diameter of a sphere with a volume of 80487 in3 to the nearest tenth ofan inch class=

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MihiraO544792 MihiraO544792
  • 26-10-2022

EXPLANATION

If the volume of a sphere is 80487 in^3, the diameter would be given by the following relationship:

[tex]\text{Volume}=\frac{4}{3}\cdot\pi\cdot r^3[/tex]

Replacing terms:

[tex]80487=\frac{4}{3}\cdot\pi\cdot r^3[/tex]

Isolating r^3:

[tex]\frac{80487}{\pi}\cdot\frac{3}{4}=r^3[/tex]

Applying the cubic root to both sides:

[tex]\sqrt[]{\frac{80487}{\pi}\cdot\frac{3}{4}}=r[/tex]

Switching sides:

[tex]r=\sqrt[]{\frac{80487}{\pi}\cdot\frac{3}{4}}[/tex]

Multiplying numbers:

[tex]undefined[/tex]

Answer Link

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