We want to find the width of the enlargement, where its length is 40 inches, and the original size is 20 inches wide and 25 inches tall.
We can state a proportion, calling by x the width of the enlargement, and we get:
[tex]\frac{20}{25}=\frac{x}{40}[/tex]
We multiply means and extremes:
[tex]\begin{gathered} 20\cdot40=25\cdot x \\ 800=25\cdot x \\ \text{And we solve for x:} \\ x=\frac{800}{25}=32 \end{gathered}[/tex]
This means that the width of the enlargement 32 inches.
