Given the matrix:
[tex]\begin{bmatrix}{-1} & {4} \\ {5} & {6}\end{bmatrix}[/tex]
Therefore, the area of the parallelogram is the absolute determinant of the matrix.
[tex]|det\begin{bmatrix}{-1} & {4} \\ {5} & {6}\end{bmatrix}|=|(-1\times6)-(5\times4)|=|-6-20|=|-26|=26[/tex]
Hence, the answer is
[tex]26unit^2\text{ \lparen Option B\rparen}[/tex]
