JiseleF370193 JiseleF370193
  • 26-10-2022
  • Mathematics
contestada

f(x)=(x+2)^2+6Equation of axis of symmetry of parabola.

Respuesta :

JustinaC385660 JustinaC385660
  • 26-10-2022

Solution

For this case we have the following function:

[tex]y=(x+2)^2+6[/tex]

We can expand the terms and we have:

y= x^2 +4x+4 +6 = x^2 +4x+10

And then we can find the equation for the axis of symettry with:

[tex]y=-\frac{b}{2a}[/tex]

a= 1, b= 4 then

[tex]y=-\frac{4}{2\cdot1}=-2[/tex]

Then the answer for this case is:

y= -2

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