Given:
The mass of the ice is m = 150 g
Required: The heat required to convert ice to water at zero degrees Celsius.
Explanation:
The heat can be calculated by the formula
[tex]Q=mL_f[/tex]Here, the latent heat of fusion is
[tex]L_f=\text{ 80 cal/g}[/tex]On substituting the values, the heat will be
[tex]\begin{gathered} Q=150\text{ g}\times\frac{80cal}{g} \\ =12000\text{ cal} \end{gathered}[/tex]Final Answer: The heat required to convert ice to water at zero degrees Celsius is 12000 calories.
