Answer:
14x-5y-11=0
Step-by-step explanation:
Given
point (x1, y1)=(-1,-5)
slope (m)=14/5
Now using the formula
the equation of the line through the point of (x1, y1) and have the slope of m is
(y-y1)=m(x-x1)
(y-(-5))=(14/5)(x-(-1))
(y+5)=(14/5)(x+1)
(y+5)=(14x+14)/5
cross multiplication
5(y+5)=14x+14
5y+25=14x+14
14x-5y+14-25=0
14x-5y-11=0
