The measure of m<BAC is 54,5 degrees
Addition postulate
From the given figure, we have the following sum;
<BAC + <CAD = <BAD
Given the following
m∠BAD = 146º
<BAC = 4x-19
<CAD = 4x + 18
Substitute
4x-19+4x+18 = 146
8x = 146 + 1
8x = 147
x = 147/8
x = 18.375
For m<BAC
m<BAC = 4x - 19
m,BAC = 4(18.375) - 19
m<BAC = 54.5 degres
Hence the measure of m<BAC is 54,5 degrees
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