Answer:
Step-by-step explanation:
eq. of line is 2x-3y=-3
its slope=(-co-efficient of x/co-efficient of y)=-2/-3=2/3
slope of line perpendicular to given line=-3/2
eq. of line through (-3,0) is
y-0=-3/2 (x+3)
2y=-3x-9
3x+2y=-9
or
any eq. perpendicular to given line is
3x+2y=c where c is a constant.
it passes through (-3,0)
3(-3)+2(0)=c
c=-9
reqd. eq. is
3x+2y=-9
