Answer:
406
Step-by-step explanation:
let the 5 consecutive positive integers be
n , n + 1 , n + 2 , n + 3 , n + 4 , then
n + n + 1 + n + 2 + n + 3 + n + 4 = 2020
5n + 10 = 2020 ( subtract 10 from both sides )
5n = 2010 ( divide both sides by 5 )
n = 402
then
largest integer = n + 4 = 402 + 4 = 406
