Answer: -4, -3, -2
Step-by-step explanation:
By inspection, we know [tex]x=-2[/tex] is a root.
We can thus rewrite the equation as
[tex](x+2)\left(\frac{x^3 + 9x^2 + 26x+24}{x+2} \right)=0\\\\(x+2)(x^2 + 7x+12)=0\\\\(x+2)(x+3)(x+4)=0\\\\x=-4, -3, -2[/tex]
