In h(x) = 4x^2 + 3x - 2, there is an x contained with h as well as an x in the expression. To find h(j + 1), we'll need to plug in (j + 1) everywhere that there is an x.
h(j + 1) = 4(j + 1)^2 + 3(j + 1) - 2
h(j + 1) = 4(j^2 + 2j + 1) + 3j + 3 - 2
h(j + 1) = 4j^2 + 8j + 4 + 3j + 3 - 2
h(j + 1) = 4j^2 + 11j + 5
Hope this helps!
