irfanchowdhury011 irfanchowdhury011
  • 29-05-2022
  • Mathematics
contestada

Multiply
[(x-1)/(x^2-2x-3)].[(3x-9)/(x+2)]

Respuesta :

Аноним Аноним
  • 29-05-2022

Answer:

3(x -1) / (x + 1)(x + 2).

Step-by-step explanation:

(x-1)/(x^2-2x-3)].[(3x-9)/(x+2)

Factoring the denominator  and 3x - 9:

= (x - 1) / (x + 1)(x - 3)  *  3(x - 3) / (x + 2)

The (x - 3)'s  cancel out, so we have:

(x - 1)/(x + 1) * 3 / (x + 2)

= 3(x -1) / (x + 1)(x + 2).

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