Respuesta :

loneguy

[tex]\text{Given that,}\\\\~~~~~~~\text{Area} = 25\pi\\\\\implies \pi r^2 = 25 \pi\\\\\implies r^2 = 25\\\\\implies r= 5\\\\\text{Now,}\\\\\text{Circumference}= 2\pi r\\\\~~~~~~~~~~~~~~~~~~~~=2\pi \cdot 5\\ \\~~~~~~~~~~~~~~~~~~~~=10\pi[/tex]

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