mxyqu8kqh6 mxyqu8kqh6
  • 28-05-2022
  • Mathematics
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Can somebody help me with this? Please and Thank you

Can somebody help me with this Please and Thank you class=

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loneguy
loneguy loneguy
  • 28-05-2022

[tex]\text{Given that,}~ p(x) = x^2 +3 ~ \text{and}~ h(x) = \sqrt{x-3} \\\\(p \circ h)(x)\\\\=p(h(x))\\\\=p\left(\sqrt{x-3}\right)\\\\=\left(\sqrt{x-3} \right)^2 +3\\\\=x-3 +3\\\\=x[/tex]

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