prayerallen2000 prayerallen2000
  • 28-04-2022
  • Chemistry
contestada


How much heat must be removed from 75.0 g of water at 90.0°C to cool it to 23.0°C?

Respuesta :

jsimpson11000 jsimpson11000
  • 06-05-2022

Answer:

See below

Explanation:

75 g * ( 90 - 23) C   *  1 cal / g-C

= 5025 cal     =    21 034 .7 J

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