jxdelacerda64
jxdelacerda64 jxdelacerda64
  • 27-04-2022
  • Mathematics
contestada

. What is the vertical asymptote(s) for y=x-5/x^2-4x-12​

Respuesta :

carmenparedes091906 carmenparedes091906
  • 27-04-2022

Answer:

4x=5y

Step-by-step explanation:

it gave the answer

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Аноним Аноним
  • 27-04-2022

Answer:

x = -2 and 6

Step-by-step explanation:

To find vertical asymptote, set the denominator equal to 0 and solve for x. See the guidelines below for determining VA

[tex]y=\frac{x-5}{x^{2} -4x-12}[/tex]

[tex]x^{2} -4x-12=0[/tex]

[tex]x^{2} -6x+2x-12=0[/tex]

[tex]x(x-6)+2(x-6)=0[/tex]

[tex](x+2)(x-6)=0[/tex]

[tex]x=-2,6[/tex]

Hope this helps and God bless!

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