1, 3, 5, 7, 9 ......
notice, there are consecutive odd integers, every other number
skip one, another, skip one, another and so on
so, from 1 to 3, is 1 + 2 =3
5 is 3 +2
7 is 5+2
and so on
let us pick an odd integer, hmmm say "a"
to find the next odd one, it'd be "a + 2" of course :)
we know their sum is 316
so [tex]\bf a+(a+2)=316\impliedby \textit{solve for "a"}[/tex]
once you found "a", the next one is, well, "a + 2" :)
