[tex]\bf sec(60^o)-sin(60^o)\qquad
\begin{cases}
sec(\theta)=\cfrac{1}{cos(\theta)}\\
------------\\
sin(60^o)\implies \cfrac{\sqrt{3}}{2}
\\ \quad \\
cos(60^o)\implies \cfrac{1}{2}
\end{cases}
\\ \quad \\ \quad \\
sec(60^o)-sin(60^o)\implies \cfrac{1}{cos(60^o)}-sin(60^o)
\\ \quad \\
\cfrac{1}{\frac{1}{2}}-\cfrac{\sqrt{3}}{2}\implies \cfrac{1}{1}\cdot \cfrac{2}{1}-\cfrac{\sqrt{3}}{2}\implies 2-\cfrac{\sqrt{3}}{2}
\\ \quad \\
\textit{our LCD will be "2", thus}
\\ \quad \\
\cfrac{4-\sqrt{3}}{2}[/tex]
