we have
[tex]r(x) = 3x - 1\\s(x) = 2x + 1[/tex]
we know that
the ratio [tex]\frac{r}{s}(x)[/tex] is equal to
[tex]\frac{3x-1}{2x+1}[/tex]
for [tex]x=6[/tex]
substitute the value of x in the equation
[tex]\frac{3(6)-1}{2(6)+1}[/tex]
therefore
the answer is the first option
[tex]\frac{3(6)-1}{2(6)+1}[/tex]
