Respuesta :

LammettHash
[tex]\dfrac{\sqrt{81+x^2}}x=\dfrac{\sqrt{81+(9\tan\theta)^2}}{9\tan\theta}=\dfrac{\sqrt{81+81\tan^2\theta}}{9\tan\theta}=\dfrac{9\sqrt{1+\tan^2\theta}}{9\tan\theta}=\dfrac{\sqrt{\sec^2\theta}}{\tan\theta}=\dfrac{|\sec\theta|}{\tan\theta}[/tex]

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