Respuesta :

Eyadaqrabawi

h(t)= t² -2t

h(x-5) = (x-5)²- 2(x-5)

= x² - 10x + 25 -2x +10

x² -12x +35

[tex]h(t)=t^2-2t\qquad \qquad h(x-5)=(x-5)^2-2(x-5) \\\\\\ h(x-5)=(x-5)(x-5)-2x+10 \\\\\\ h(x-5)=\stackrel{F~O~I~L}{(x^2-10x+25)}-2x+10 \implies h(x-5)=x^2-12x+35[/tex]

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